Menu Top
Non-Rationalised Science NCERT Notes and Solutions (Class 6th to 10th)
6th 7th 8th 9th 10th
Non-Rationalised Science NCERT Notes and Solutions (Class 11th)
Physics Chemistry Biology
Non-Rationalised Science NCERT Notes and Solutions (Class 12th)
Physics Chemistry Biology

Class 9th Chapters
1. Matter In Our Surroundings 2. Is Matter Around Us Pure? 3. Atoms And Molecules
4. Structure Of The Atom 5. The Fundamental Unit Of Life 6. Tissues
7. Diversity In Living Organisms 8. Motion 9. Force And Laws Of Motion
10. Gravitation 11. Work And Energy 12. Sound
13. Why Do We Fall Ill? 14. Natural Resources 15. Improvement In Food Resources



Chapter 4: Structure Of The Atom



In earlier chapters, we established that atoms and molecules are the basic building blocks of matter. The diversity of matter around us arises from the different types of atoms that compose it.

This leads to fundamental questions: What distinguishes the atom of one element from that of another? And are atoms truly indivisible as previously thought, or do they contain even smaller constituents?

By the late 19th century, scientists faced the significant challenge of understanding the internal structure of the atom and how its components determined its properties. Experiments studying the behaviour of electricity provided the first clues that atoms were not indivisible.


Charged Particles In Matter

Simple experiments involving static electricity suggest the presence of charged particles within matter. For example, rubbing a comb through dry hair causes the comb to attract small pieces of paper, and rubbing a glass rod with silk makes it attract a balloon. This indicates that friction can transfer electrical charges between objects.

The source of these charges implies that atoms themselves are not electrically neutral particles as a whole, but rather contain charged constituents.

By around 1900, despite the prevailing view of atoms as indivisible, it became clear they contained smaller particles.

Initial understanding suggested atoms were composed of equal numbers of protons and electrons, balancing their charges to make the atom electrically neutral overall. The key question then became how these particles were arranged within the atomic structure.



The Structure Of An Atom

The discovery of electrons and protons contradicted Dalton's idea of the atom as an indivisible and indestructible particle. This necessitated new models to explain the arrangement of these sub-atomic particles within the atom.

J.J. Thomson proposed the first formal model for the structure of an atom.


Thomson’s Model Of An Atom

Thomson's model is often compared to a Christmas pudding or a watermelon.

Diagram showing Thomson's Plum Pudding model of an atom, depicting a positive sphere with negative electrons embedded in it

Key Postulates of Thomson's Model:

  1. An atom consists of a uniformly positively charged sphere.
  2. The electrons (negative charges) are embedded within this positive sphere, like plums in a pudding or seeds in a watermelon.
  3. The total positive charge of the sphere is equal in magnitude to the total negative charge from the electrons. This ensures that the atom as a whole is electrically neutral.

Thomson's model successfully explained the overall electrical neutrality of atoms. However, it failed to explain the results of later experiments conducted by other scientists, particularly Rutherford's alpha-particle scattering experiment.


Rutherford’s Model Of An Atom

Ernest Rutherford, a student of J.J. Thomson, sought to understand the arrangement of electrons by conducting the famous alpha-particle scattering experiment.

Experimental Setup: Fast-moving alpha ($\alpha$) particles (which are positively charged helium ions, He²⁺, with a mass of 4 u) were directed towards a very thin sheet of gold foil (approximately 1000 atoms thick). A fluorescent screen was placed around the foil to detect the deflection of the $\alpha$-particles.

Diagram showing Rutherford's alpha-particle scattering experiment setup: alpha particle source, gold foil, scattered alpha particles detected on a screen.

Rutherford expected the massive $\alpha$-particles to pass straight through the foil or be deflected only slightly by the sub-atomic particles within the gold atoms, as per Thomson's model.

Unexpected Observations:

  1. Most (about 99.9%) of the fast $\alpha$-particles passed straight through the gold foil without any deflection.
  2. A small fraction of the $\alpha$-particles were deflected by small angles.
  3. A very small number (about 1 in 12,000) of the $\alpha$-particles were deflected by large angles or even appeared to rebound almost back towards the source (deflection of 180$^\circ$).

Rutherford described the rebounding of $\alpha$-particles as "almost as incredible as if you fire a 15-inch shell at a piece of tissue paper and it comes back and hits you."

Conclusions Drawn from Observations: Based on these unexpected results, Rutherford made the following conclusions, reasoning much like a blindfolded child throwing stones at a wall vs. a barbed-wire fence:

  1. The fact that most $\alpha$-particles passed straight through indicated that most of the space inside an atom is empty.
  2. The deflection of some $\alpha$-particles suggested that there is a small, positively charged region within the atom that repelled the positive $\alpha$-particles. This positive charge must occupy very little volume.
  3. The occasional large-angle deflection or rebound implied that the entire positive charge and almost all the mass of the atom are concentrated in a very small volume at the centre.

Based on his experiment, Rutherford proposed the Nuclear Model of the Atom.

Features of Rutherford’s Nuclear Model:

  1. There is a positively charged centre in the atom called the nucleus. Nearly all the mass of the atom is concentrated in the nucleus.
  2. The electrons revolve around the nucleus in well-defined circular paths (orbits).
  3. The size of the nucleus is very small compared to the overall size of the atom. Rutherford calculated that the radius of the nucleus is about $10^5$ times smaller than the radius of the atom.

Drawbacks Of Rutherford’s Model Of The Atom

Despite introducing the concept of a nucleus, Rutherford's model faced significant challenges regarding the stability of the atom.

According to classical physics, a charged particle in circular motion (like an electron revolving around the nucleus) undergoes acceleration. An accelerating charged particle is expected to radiate energy continuously.

If the orbiting electrons continuously lost energy, they would spiral inwards and eventually fall into the nucleus. This would cause the atom to collapse, making it highly unstable.

However, we know that atoms are generally very stable and do not collapse. Rutherford's model could not explain this stability of the atom, which was a major limitation.


Bohr’s Model Of Atom

To address the stability problem of Rutherford's model, Neils Bohr proposed a modified model of the atom incorporating some quantum mechanical concepts.

Postulates of Bohr's Model:

  1. Only certain special orbits, known as discrete orbits or stationary states, are allowed for electrons inside the atom. Electrons can only revolve in these specific orbits.
  2. While revolving in these discrete orbits, the electrons do not radiate energy. This explains why the atom is stable and the electrons don't spiral into the nucleus.

These allowed orbits are also referred to as energy levels or shells. They are represented by letters K, L, M, N, ... or by numbers n = 1, 2, 3, 4, ... starting from the nucleus (n=1 corresponds to the K shell).

Diagram showing Bohr's model with a central nucleus and electrons orbiting in distinct shells labeled K, L, M, N (n=1, 2, 3, 4)

Electrons gain or lose energy only when they move from one energy level to another.


Neutrons

In 1932, James Chadwick discovered another sub-atomic particle within the nucleus. This particle had:

This particle was named the neutron (n).

Neutrons are present in the nucleus of all atoms, except for the simplest isotope of hydrogen (Protium).

Protons and neutrons together reside in the nucleus and are collectively called nucleons.

The mass of an atom is effectively the sum of the masses of the protons and neutrons in its nucleus, as the mass of electrons is negligible.

For example, a carbon atom with 6 protons and 6 neutrons has a mass of approximately 6 u (from protons) + 6 u (from neutrons) = 12 u. An aluminium atom with 13 protons and 14 neutrons has a mass of approximately 13 u + 14 u = 27 u.



How Are Electrons Distributed In Different Orbits (Shells)?

The arrangement of electrons in the various energy levels or shells around the nucleus is described by the Bohr-Bury scheme. This scheme follows certain rules for distributing electrons:

  1. The maximum number of electrons that a shell can hold is given by the formula $2n^2$, where 'n' is the number of the orbit or energy level (n=1 for K shell, n=2 for L shell, n=3 for M shell, etc.).
    • K-shell (n=1): Maximum electrons = $2 \times 1^2 = 2$
    • L-shell (n=2): Maximum electrons = $2 \times 2^2 = 8$
    • M-shell (n=3): Maximum electrons = $2 \times 3^2 = 18$
    • N-shell (n=4): Maximum electrons = $2 \times 4^2 = 32$, and so on.
  2. The outermost shell of an atom cannot accommodate more than 8 electrons, regardless of the $2n^2$ rule for inner shells.
  3. Electrons fill the shells in a step-wise manner, starting from the innermost shell (K shell). A new shell is filled only after the inner shells are completely filled.

Following these rules, we can determine the electron distribution (electronic configuration) for atoms of different elements. For a neutral atom, the number of electrons is equal to the number of protons (atomic number).



Valency

The electrons located in the outermost shell of an atom are called valence electrons.

Atoms of elements with a completely filled outermost shell are chemically unreactive or inert (e.g., Noble gases like Helium with 2 electrons in K shell, and Neon or Argon with 8 electrons in their outermost shells). Their combining capacity is considered zero.

The tendency of atoms to react and form chemical bonds is driven by the desire to achieve a stable electron configuration in their outermost shell, similar to that of noble gases. For most atoms (except hydrogen and helium), this stable configuration is having eight electrons in the outermost shell, known as the octet rule.

Atoms achieve this octet by gaining, losing, or sharing valence electrons with other atoms.

The valency of an element is defined as the combining capacity of its atom. It is determined by the number of electrons an atom needs to gain, lose, or share to attain a stable outermost shell configuration (usually an octet).

Examples:

Valency represents the number of electrons involved in forming bonds and determines how atoms combine to form compounds.



Atomic Number And Mass Number

The identity and properties of an element are fundamentally determined by the number of protons in its atoms.


Atomic Number

The atomic number (Z) of an element is defined as the total number of protons present in the nucleus of an atom of that element.

Every atom of a particular element has the exact same atomic number. The atomic number is unique to each element and serves as its defining characteristic. For example, any atom with 1 proton is Hydrogen (Z=1), any atom with 6 protons is Carbon (Z=6).

For a neutral atom, the number of electrons orbiting the nucleus is equal to the number of protons in the nucleus (Number of electrons = Z).


Mass Number

The mass of an atom is primarily concentrated in its nucleus due to the presence of protons and neutrons, which have significantly greater mass than electrons. As discussed, protons and neutrons are called nucleons.

The mass number (A) of an atom is defined as the sum of the total number of protons and neutrons present in its nucleus.

$ \text{Mass Number (A)} = \text{Number of Protons (Z)} + \text{Number of Neutrons} $

To represent an atom, the atomic number, mass number, and symbol of the element are often written together in the following format:

$$ \textsf{}_{\text{Z}}^{\text{A}}\text{X} $$

Where X is the symbol of the element, A is the mass number, and Z is the atomic number.

For example, Nitrogen (N) has 7 protons and typically 7 neutrons. Its atomic number Z=7 and mass number A = 7+7=14. It is represented as $\text{}_{\text{7}}^{\text{14}}\text{N}$.



Isotopes

Experiments revealed that atoms of the same element can sometimes have slightly different masses. This led to the discovery of isotopes.

Definition: Isotopes are atoms of the same element that have the same atomic number (Z) but different mass numbers (A). This difference in mass number arises because isotopes of an element have the same number of protons but a different number of neutrons.

Examples:

Many elements in nature exist as a mixture of two or more isotopes. Each individual isotope is considered a pure substance.

Properties of Isotopes:

Since elements exist as isotopic mixtures, the atomic mass listed for an element on the periodic table is usually an average atomic mass. This average is calculated based on the masses of its naturally occurring isotopes and their relative abundances (percentages).

Example: Calculating Average Atomic Mass of Chlorine:

Natural chlorine exists as $\text{}_{\text{17}}^{\text{35}}\text{Cl}$ with a mass of 35 u (approx.) and $\text{}_{\text{17}}^{\text{37}}\text{Cl}$ with a mass of 37 u (approx.). Their relative abundance in nature is approximately 3:1, meaning 75% is $^{35}\text{Cl}$ and 25% is $^{37}\text{Cl}$.

Average Atomic Mass of Cl = $( \text{Mass of } ^{35}\text{Cl} \times \text{Percentage Abundance} ) + ( \text{Mass of } ^{37}\text{Cl} \times \text{Percentage Abundance} )$

Average Atomic Mass of Cl = $ (35 \text{ u} \times \frac{75}{100}) + (37 \text{ u} \times \frac{25}{100}) $

Average Atomic Mass of Cl = $ (35 \times 0.75) \text{ u} + (37 \times 0.25) \text{ u} $

Average Atomic Mass of Cl = $ 26.25 \text{ u} + 9.25 \text{ u} = 35.5 \text{ u} $

The average atomic mass of chlorine is 35.5 u. This means a sample of natural chlorine will have this average mass per atom, even though no single chlorine atom actually has a mass of 35.5 u.


Applications

While isotopes of an element behave similarly chemically, some isotopes have specific physical or nuclear properties that make them useful in various fields:


Isobars

In contrast to isotopes, which are atoms of the same element, isobars are atoms of different elements that have the same mass number (A) but different atomic numbers (Z).

Since isobars are atoms of different elements, they have different numbers of protons and electrons, and therefore different chemical properties.

Example:

Calcium and Argon are isobars because they have the same mass number (A=40) but different atomic numbers (Z=20 and Z=18).



Intext Questions



Page No. 47

Question 1. What are canal rays?

Answer:

Question 2. If an atom contains one electron and one proton, will it carry any charge or not?

Answer:



Page No. 49

Question 1. On the basis of Thomson’s model of an atom, explain how the atom is neutral as a whole.

Answer:

Question 2. On the basis of Rutherford’s model of an atom, which subatomic particle is present in the nucleus of an atom?

Answer:

Question 3. Draw a sketch of Bohr’s model of an atom with three shells.

Answer:

Question 4. What do you think would be the observation if the $\alpha$-particle scattering experiment is carried out using a foil of a metal other than gold?

Answer:





Question 1. Name the three sub-atomic particles of an atom.

Answer:

Question 2. Helium atom has an atomic mass of 4 u and two protons in its nucleus. How many neutrons does it have?

Answer:



Page No. 50

Question 1. Write the distribution of electrons in carbon and sodium atoms.

Answer:

Question 2. If K and L shells of an atom are full, then what would be the total number of electrons in the atom?

Answer:



Page No. 52

Question 1. How will you find the valency of chlorine, sulphur and magnesium?

Answer:





Question 1. If number of electrons in an atom is 8 and number of protons is also 8, then (i) what is the atomic number of the atom? and (ii) what is the charge on the atom?

Answer:

Question 2. With the help of Table 4.1, find out the mass number of oxygen and sulphur atom.

Answer:



Page No. 53

Question 1. For the symbol H,D and T tabulate three sub-atomic particles found in each of them.

Answer:

Question 2. Write the electronic configuration of any one pair of isotopes and isobars.

Answer:



Exercises



Question 1. Compare the properties of electrons, protons and neutrons.

Answer:

Question 2. What are the limitations of J.J. Thomson’s model of the atom?

Answer:

Question 3. What are the limitations of Rutherford’s model of the atom?

Answer:

Question 4. Describe Bohr’s model of the atom.

Answer:

Question 5. Compare all the proposed models of an atom given in this chapter.

Answer:

Question 6. Summarise the rules for writing of distribution of electrons in various shells for the first eighteen elements.

Answer:

Question 7. Define valency by taking examples of silicon and oxygen.

Answer:

Question 8. Explain with examples (i) Atomic number, (ii) Mass number, (iii) Isotopes and iv) Isobars. Give any two uses of isotopes.

Answer:

Question 9. $Na^+$ has completely filled K and L shells. Explain.

Answer:

Question 10. If bromine atom is available in the form of, say, two isotopes $ ^{79}_{35}Br $ (49.7%) and $ ^{81}_{35}Br $ (50.3%), calculate the average atomic mass of bromine atom.

Answer:

Question 11. The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes $ ^{16}_{8}X $ and $ ^{18}_{8}X $ in the sample?

Answer:

Question 12. If Z = 3, what would be the valency of the element? Also, name the element.

Answer:

Question 13. Composition of the nuclei of two atomic species X and Y are given as under

$$ \begin{matrix} & X & Y \\ Protons = & 6 & 6 \\ Neutrons = & 6 & 8 \end{matrix} $$

Give the mass numbers of X and Y. What is the relation between the two species?

Answer:

Question 14. For the following statements, write T for True and F for False.

(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons.

(b) A neutron is formed by an electron and a proton combining together. Therefore, it is neutral.

(c) The mass of an electron is about $\frac{1}{2000}$ times that of proton.

(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine.

Answer:

Put tick (✓) against correct choice and cross (×) against wrong choice in questions 15, 16 and 17

Question 15. Rutherford’s alpha-particle scattering experiment was responsible for the discovery of

(a) Atomic Nucleus

(b) Electron

(c) Proton

(d) Neutron

Answer:

Question 16. Isotopes of an element have

(a) the same physical properties

(b) different chemical properties

(c) different number of neutrons

(d) different atomic numbers.

Answer:

Question 17. Number of valence electrons in $Cl^–$ ion are:

(a) 16

(b) 8

(c) 17

(d) 18

Answer:

Question 18. Which one of the following is a correct electronic configuration of sodium?

(a) 2,8

(b) 8,2,1

(c) 2,1,8

(d) 2,8,1.

Answer:

Question 19. Complete the following table.

Atomic Number Mass Number Number of Neutrons Number of Protons Number of Electrons Name of the Atomic Species
9 - 10 - - -
16 32 - - - Sulphur
- 24 - 12 - -
- 2 - 1 - -
- 1 0 1 0 -

Answer: